3.1.29 \(\int \frac {d+e x+f x^2+g x^3+h x^4}{(4-5 x^2+x^4)^2} \, dx\)

Optimal. Leaf size=150 \[ \frac {x \left (-\left (x^2 (5 d+8 f+20 h)\right )+17 d+20 f+32 h\right )}{72 \left (x^4-5 x^2+4\right )}+\frac {1}{432} \tanh ^{-1}\left (\frac {x}{2}\right ) (19 d+52 f+112 h)-\frac {1}{54} \tanh ^{-1}(x) (d+7 f+13 h)+\frac {1}{54} (2 e+5 g) \log \left (1-x^2\right )-\frac {1}{54} (2 e+5 g) \log \left (4-x^2\right )+\frac {-\left (x^2 (2 e+5 g)\right )+5 e+8 g}{18 \left (x^4-5 x^2+4\right )} \]

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Rubi [A]  time = 0.21, antiderivative size = 150, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 8, integrand size = 33, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.242, Rules used = {1673, 1678, 1166, 207, 1247, 638, 616, 31} \begin {gather*} \frac {x \left (x^2 (-(5 d+8 f+20 h))+17 d+20 f+32 h\right )}{72 \left (x^4-5 x^2+4\right )}+\frac {1}{432} \tanh ^{-1}\left (\frac {x}{2}\right ) (19 d+52 f+112 h)-\frac {1}{54} \tanh ^{-1}(x) (d+7 f+13 h)+\frac {x^2 (-(2 e+5 g))+5 e+8 g}{18 \left (x^4-5 x^2+4\right )}+\frac {1}{54} (2 e+5 g) \log \left (1-x^2\right )-\frac {1}{54} (2 e+5 g) \log \left (4-x^2\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(d + e*x + f*x^2 + g*x^3 + h*x^4)/(4 - 5*x^2 + x^4)^2,x]

[Out]

(5*e + 8*g - (2*e + 5*g)*x^2)/(18*(4 - 5*x^2 + x^4)) + (x*(17*d + 20*f + 32*h - (5*d + 8*f + 20*h)*x^2))/(72*(
4 - 5*x^2 + x^4)) + ((19*d + 52*f + 112*h)*ArcTanh[x/2])/432 - ((d + 7*f + 13*h)*ArcTanh[x])/54 + ((2*e + 5*g)
*Log[1 - x^2])/54 - ((2*e + 5*g)*Log[4 - x^2])/54

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 207

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTanh[(Rt[b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && NegQ[a/b] && (LtQ[a, 0] || GtQ[b, 0])

Rule 616

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = Rt[b^2 - 4*a*c, 2]}, Dist[c/q, Int[1/Simp
[b/2 - q/2 + c*x, x], x], x] - Dist[c/q, Int[1/Simp[b/2 + q/2 + c*x, x], x], x]] /; FreeQ[{a, b, c}, x] && NeQ
[b^2 - 4*a*c, 0] && PosQ[b^2 - 4*a*c] && PerfectSquareQ[b^2 - 4*a*c]

Rule 638

Int[((d_.) + (e_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[((b*d - 2*a*e + (2*c*d -
b*e)*x)*(a + b*x + c*x^2)^(p + 1))/((p + 1)*(b^2 - 4*a*c)), x] - Dist[((2*p + 3)*(2*c*d - b*e))/((p + 1)*(b^2
- 4*a*c)), Int[(a + b*x + c*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e}, x] && NeQ[2*c*d - b*e, 0] && NeQ[b^
2 - 4*a*c, 0] && LtQ[p, -1] && NeQ[p, -3/2]

Rule 1166

Int[((d_) + (e_.)*(x_)^2)/((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[b^2 - 4*a*c, 2]}, Di
st[e/2 + (2*c*d - b*e)/(2*q), Int[1/(b/2 - q/2 + c*x^2), x], x] + Dist[e/2 - (2*c*d - b*e)/(2*q), Int[1/(b/2 +
q/2 + c*x^2), x], x]] /; FreeQ[{a, b, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - a*e^2, 0] && PosQ[b^
2 - 4*a*c]

Rule 1247

Int[(x_)*((d_) + (e_.)*(x_)^2)^(q_.)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_.), x_Symbol] :> Dist[1/2, Subst[
Int[(d + e*x)^q*(a + b*x + c*x^2)^p, x], x, x^2], x] /; FreeQ[{a, b, c, d, e, p, q}, x]

Rule 1673

Int[(Pq_)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_), x_Symbol] :> Module[{q = Expon[Pq, x], k}, Int[Sum[Coeff[
Pq, x, 2*k]*x^(2*k), {k, 0, q/2}]*(a + b*x^2 + c*x^4)^p, x] + Int[x*Sum[Coeff[Pq, x, 2*k + 1]*x^(2*k), {k, 0,
(q - 1)/2}]*(a + b*x^2 + c*x^4)^p, x]] /; FreeQ[{a, b, c, p}, x] && PolyQ[Pq, x] &&  !PolyQ[Pq, x^2]

Rule 1678

Int[(Pq_)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_), x_Symbol] :> With[{d = Coeff[PolynomialRemainder[Pq, a +
b*x^2 + c*x^4, x], x, 0], e = Coeff[PolynomialRemainder[Pq, a + b*x^2 + c*x^4, x], x, 2]}, Simp[(x*(a + b*x^2
+ c*x^4)^(p + 1)*(a*b*e - d*(b^2 - 2*a*c) - c*(b*d - 2*a*e)*x^2))/(2*a*(p + 1)*(b^2 - 4*a*c)), x] + Dist[1/(2*
a*(p + 1)*(b^2 - 4*a*c)), Int[(a + b*x^2 + c*x^4)^(p + 1)*ExpandToSum[2*a*(p + 1)*(b^2 - 4*a*c)*PolynomialQuot
ient[Pq, a + b*x^2 + c*x^4, x] + b^2*d*(2*p + 3) - 2*a*c*d*(4*p + 5) - a*b*e + c*(4*p + 7)*(b*d - 2*a*e)*x^2,
x], x], x]] /; FreeQ[{a, b, c}, x] && PolyQ[Pq, x^2] && Expon[Pq, x^2] > 1 && NeQ[b^2 - 4*a*c, 0] && LtQ[p, -1
]

Rubi steps

\begin {align*} \int \frac {d+e x+f x^2+g x^3+h x^4}{\left (4-5 x^2+x^4\right )^2} \, dx &=\int \frac {x \left (e+g x^2\right )}{\left (4-5 x^2+x^4\right )^2} \, dx+\int \frac {d+f x^2+h x^4}{\left (4-5 x^2+x^4\right )^2} \, dx\\ &=\frac {x \left (17 d+20 f+32 h-(5 d+8 f+20 h) x^2\right )}{72 \left (4-5 x^2+x^4\right )}-\frac {1}{72} \int \frac {-d+20 f+32 h+(5 d+8 f+20 h) x^2}{4-5 x^2+x^4} \, dx+\frac {1}{2} \operatorname {Subst}\left (\int \frac {e+g x}{\left (4-5 x+x^2\right )^2} \, dx,x,x^2\right )\\ &=\frac {5 e+8 g-(2 e+5 g) x^2}{18 \left (4-5 x^2+x^4\right )}+\frac {x \left (17 d+20 f+32 h-(5 d+8 f+20 h) x^2\right )}{72 \left (4-5 x^2+x^4\right )}+\frac {1}{18} (-2 e-5 g) \operatorname {Subst}\left (\int \frac {1}{4-5 x+x^2} \, dx,x,x^2\right )-\frac {1}{54} (-d-7 f-13 h) \int \frac {1}{-1+x^2} \, dx-\frac {1}{216} (19 d+52 f+112 h) \int \frac {1}{-4+x^2} \, dx\\ &=\frac {5 e+8 g-(2 e+5 g) x^2}{18 \left (4-5 x^2+x^4\right )}+\frac {x \left (17 d+20 f+32 h-(5 d+8 f+20 h) x^2\right )}{72 \left (4-5 x^2+x^4\right )}+\frac {1}{432} (19 d+52 f+112 h) \tanh ^{-1}\left (\frac {x}{2}\right )-\frac {1}{54} (d+7 f+13 h) \tanh ^{-1}(x)+\frac {1}{54} (-2 e-5 g) \operatorname {Subst}\left (\int \frac {1}{-4+x} \, dx,x,x^2\right )+\frac {1}{54} (2 e+5 g) \operatorname {Subst}\left (\int \frac {1}{-1+x} \, dx,x,x^2\right )\\ &=\frac {5 e+8 g-(2 e+5 g) x^2}{18 \left (4-5 x^2+x^4\right )}+\frac {x \left (17 d+20 f+32 h-(5 d+8 f+20 h) x^2\right )}{72 \left (4-5 x^2+x^4\right )}+\frac {1}{432} (19 d+52 f+112 h) \tanh ^{-1}\left (\frac {x}{2}\right )-\frac {1}{54} (d+7 f+13 h) \tanh ^{-1}(x)+\frac {1}{54} (2 e+5 g) \log \left (1-x^2\right )-\frac {1}{54} (2 e+5 g) \log \left (4-x^2\right )\\ \end {align*}

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Mathematica [A]  time = 0.07, size = 159, normalized size = 1.06 \begin {gather*} \frac {1}{864} \left (-\frac {12 \left (x \left (d \left (5 x^2-17\right )+4 f \left (2 x^2-5\right )+4 h \left (5 x^2-8\right )\right )+4 e \left (2 x^2-5\right )+4 g \left (5 x^2-8\right )\right )}{x^4-5 x^2+4}+8 \log (1-x) (d+4 e+7 f+10 g+13 h)-\log (2-x) (19 d+32 e+52 f+80 g+112 h)-8 \log (x+1) (d-4 e+7 f-10 g+13 h)+\log (x+2) (19 d-32 e+52 f-80 g+112 h)\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(d + e*x + f*x^2 + g*x^3 + h*x^4)/(4 - 5*x^2 + x^4)^2,x]

[Out]

((-12*(4*e*(-5 + 2*x^2) + 4*g*(-8 + 5*x^2) + x*(4*f*(-5 + 2*x^2) + d*(-17 + 5*x^2) + 4*h*(-8 + 5*x^2))))/(4 -
5*x^2 + x^4) + 8*(d + 4*e + 7*f + 10*g + 13*h)*Log[1 - x] - (19*d + 32*e + 52*f + 80*g + 112*h)*Log[2 - x] - 8
*(d - 4*e + 7*f - 10*g + 13*h)*Log[1 + x] + (19*d - 32*e + 52*f - 80*g + 112*h)*Log[2 + x])/864

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {d+e x+f x^2+g x^3+h x^4}{\left (4-5 x^2+x^4\right )^2} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[(d + e*x + f*x^2 + g*x^3 + h*x^4)/(4 - 5*x^2 + x^4)^2,x]

[Out]

IntegrateAlgebraic[(d + e*x + f*x^2 + g*x^3 + h*x^4)/(4 - 5*x^2 + x^4)^2, x]

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fricas [B]  time = 5.98, size = 304, normalized size = 2.03 \begin {gather*} -\frac {12 \, {\left (5 \, d + 8 \, f + 20 \, h\right )} x^{3} + 48 \, {\left (2 \, e + 5 \, g\right )} x^{2} - 12 \, {\left (17 \, d + 20 \, f + 32 \, h\right )} x - {\left ({\left (19 \, d - 32 \, e + 52 \, f - 80 \, g + 112 \, h\right )} x^{4} - 5 \, {\left (19 \, d - 32 \, e + 52 \, f - 80 \, g + 112 \, h\right )} x^{2} + 76 \, d - 128 \, e + 208 \, f - 320 \, g + 448 \, h\right )} \log \left (x + 2\right ) + 8 \, {\left ({\left (d - 4 \, e + 7 \, f - 10 \, g + 13 \, h\right )} x^{4} - 5 \, {\left (d - 4 \, e + 7 \, f - 10 \, g + 13 \, h\right )} x^{2} + 4 \, d - 16 \, e + 28 \, f - 40 \, g + 52 \, h\right )} \log \left (x + 1\right ) - 8 \, {\left ({\left (d + 4 \, e + 7 \, f + 10 \, g + 13 \, h\right )} x^{4} - 5 \, {\left (d + 4 \, e + 7 \, f + 10 \, g + 13 \, h\right )} x^{2} + 4 \, d + 16 \, e + 28 \, f + 40 \, g + 52 \, h\right )} \log \left (x - 1\right ) + {\left ({\left (19 \, d + 32 \, e + 52 \, f + 80 \, g + 112 \, h\right )} x^{4} - 5 \, {\left (19 \, d + 32 \, e + 52 \, f + 80 \, g + 112 \, h\right )} x^{2} + 76 \, d + 128 \, e + 208 \, f + 320 \, g + 448 \, h\right )} \log \left (x - 2\right ) - 240 \, e - 384 \, g}{864 \, {\left (x^{4} - 5 \, x^{2} + 4\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((h*x^4+g*x^3+f*x^2+e*x+d)/(x^4-5*x^2+4)^2,x, algorithm="fricas")

[Out]

-1/864*(12*(5*d + 8*f + 20*h)*x^3 + 48*(2*e + 5*g)*x^2 - 12*(17*d + 20*f + 32*h)*x - ((19*d - 32*e + 52*f - 80
*g + 112*h)*x^4 - 5*(19*d - 32*e + 52*f - 80*g + 112*h)*x^2 + 76*d - 128*e + 208*f - 320*g + 448*h)*log(x + 2)
+ 8*((d - 4*e + 7*f - 10*g + 13*h)*x^4 - 5*(d - 4*e + 7*f - 10*g + 13*h)*x^2 + 4*d - 16*e + 28*f - 40*g + 52*
h)*log(x + 1) - 8*((d + 4*e + 7*f + 10*g + 13*h)*x^4 - 5*(d + 4*e + 7*f + 10*g + 13*h)*x^2 + 4*d + 16*e + 28*f
+ 40*g + 52*h)*log(x - 1) + ((19*d + 32*e + 52*f + 80*g + 112*h)*x^4 - 5*(19*d + 32*e + 52*f + 80*g + 112*h)*
x^2 + 76*d + 128*e + 208*f + 320*g + 448*h)*log(x - 2) - 240*e - 384*g)/(x^4 - 5*x^2 + 4)

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giac [A]  time = 0.30, size = 158, normalized size = 1.05 \begin {gather*} \frac {1}{864} \, {\left (19 \, d + 52 \, f - 80 \, g + 112 \, h - 32 \, e\right )} \log \left ({\left | x + 2 \right |}\right ) - \frac {1}{108} \, {\left (d + 7 \, f - 10 \, g + 13 \, h - 4 \, e\right )} \log \left ({\left | x + 1 \right |}\right ) + \frac {1}{108} \, {\left (d + 7 \, f + 10 \, g + 13 \, h + 4 \, e\right )} \log \left ({\left | x - 1 \right |}\right ) - \frac {1}{864} \, {\left (19 \, d + 52 \, f + 80 \, g + 112 \, h + 32 \, e\right )} \log \left ({\left | x - 2 \right |}\right ) - \frac {5 \, d x^{3} + 8 \, f x^{3} + 20 \, h x^{3} + 20 \, g x^{2} + 8 \, x^{2} e - 17 \, d x - 20 \, f x - 32 \, h x - 32 \, g - 20 \, e}{72 \, {\left (x^{4} - 5 \, x^{2} + 4\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((h*x^4+g*x^3+f*x^2+e*x+d)/(x^4-5*x^2+4)^2,x, algorithm="giac")

[Out]

1/864*(19*d + 52*f - 80*g + 112*h - 32*e)*log(abs(x + 2)) - 1/108*(d + 7*f - 10*g + 13*h - 4*e)*log(abs(x + 1)
) + 1/108*(d + 7*f + 10*g + 13*h + 4*e)*log(abs(x - 1)) - 1/864*(19*d + 52*f + 80*g + 112*h + 32*e)*log(abs(x
- 2)) - 1/72*(5*d*x^3 + 8*f*x^3 + 20*h*x^3 + 20*g*x^2 + 8*x^2*e - 17*d*x - 20*f*x - 32*h*x - 32*g - 20*e)/(x^4
- 5*x^2 + 4)

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maple [B]  time = 0.02, size = 302, normalized size = 2.01 \begin {gather*} \frac {7 h \ln \left (x +2\right )}{54}+\frac {13 h \ln \left (x -1\right )}{108}-\frac {13 h \ln \left (x +1\right )}{108}-\frac {7 h \ln \left (x -2\right )}{54}+\frac {5 g \ln \left (x -1\right )}{54}-\frac {5 g \ln \left (x +2\right )}{54}-\frac {5 g \ln \left (x -2\right )}{54}+\frac {5 g \ln \left (x +1\right )}{54}+\frac {19 d \ln \left (x +2\right )}{864}-\frac {e \ln \left (x +2\right )}{27}+\frac {e \ln \left (x -1\right )}{27}+\frac {d \ln \left (x -1\right )}{108}+\frac {e \ln \left (x +1\right )}{27}-\frac {d \ln \left (x +1\right )}{108}-\frac {19 d \ln \left (x -2\right )}{864}-\frac {e \ln \left (x -2\right )}{27}-\frac {13 f \ln \left (x -2\right )}{216}-\frac {7 f \ln \left (x +1\right )}{108}+\frac {7 f \ln \left (x -1\right )}{108}+\frac {13 f \ln \left (x +2\right )}{216}+\frac {g}{18 x +36}+\frac {g}{36 x +36}+\frac {e}{36 x +36}+\frac {e}{72 x +144}-\frac {h}{9 \left (x +2\right )}-\frac {h}{36 \left (x +1\right )}-\frac {h}{36 \left (x -1\right )}-\frac {h}{9 \left (x -2\right )}-\frac {g}{36 \left (x -1\right )}-\frac {g}{18 \left (x -2\right )}-\frac {d}{144 \left (x +2\right )}-\frac {d}{144 \left (x -2\right )}-\frac {e}{72 \left (x -2\right )}-\frac {d}{36 \left (x +1\right )}-\frac {d}{36 \left (x -1\right )}-\frac {e}{36 \left (x -1\right )}-\frac {f}{36 \left (x -1\right )}-\frac {f}{36 \left (x +2\right )}-\frac {f}{36 \left (x -2\right )}-\frac {f}{36 \left (x +1\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((h*x^4+g*x^3+f*x^2+e*x+d)/(x^4-5*x^2+4)^2,x)

[Out]

7/54*h*ln(x+2)+13/108*h*ln(x-1)-13/108*h*ln(x+1)-7/54*h*ln(x-2)+5/54*g*ln(x-1)-5/54*g*ln(x+2)-5/54*g*ln(x-2)+5
/54*g*ln(x+1)+19/864*d*ln(x+2)-1/27*e*ln(x+2)+1/27*e*ln(x-1)+1/108*d*ln(x-1)+1/27*e*ln(x+1)-1/108*d*ln(x+1)-19
/864*d*ln(x-2)-1/27*e*ln(x-2)-13/216*f*ln(x-2)-7/108*f*ln(x+1)+7/108*f*ln(x-1)+13/216*f*ln(x+2)-1/9/(x+2)*h-1/
36/(x+1)*h-1/36/(x-1)*h-1/9/(x-2)*h+1/18/(x+2)*g+1/36/(x+1)*g-1/36/(x-1)*g-1/18/(x-2)*g-1/144/(x+2)*d+1/72/(x+
2)*e-1/144/(x-2)*d-1/72/(x-2)*e-1/36/(x+1)*d+1/36/(x+1)*e-1/36/(x-1)*d-1/36/(x-1)*e-1/36/(x-1)*f-1/36/(x+2)*f-
1/36/(x-2)*f-1/36/(x+1)*f

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maxima [A]  time = 1.18, size = 145, normalized size = 0.97 \begin {gather*} \frac {1}{864} \, {\left (19 \, d - 32 \, e + 52 \, f - 80 \, g + 112 \, h\right )} \log \left (x + 2\right ) - \frac {1}{108} \, {\left (d - 4 \, e + 7 \, f - 10 \, g + 13 \, h\right )} \log \left (x + 1\right ) + \frac {1}{108} \, {\left (d + 4 \, e + 7 \, f + 10 \, g + 13 \, h\right )} \log \left (x - 1\right ) - \frac {1}{864} \, {\left (19 \, d + 32 \, e + 52 \, f + 80 \, g + 112 \, h\right )} \log \left (x - 2\right ) - \frac {{\left (5 \, d + 8 \, f + 20 \, h\right )} x^{3} + 4 \, {\left (2 \, e + 5 \, g\right )} x^{2} - {\left (17 \, d + 20 \, f + 32 \, h\right )} x - 20 \, e - 32 \, g}{72 \, {\left (x^{4} - 5 \, x^{2} + 4\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((h*x^4+g*x^3+f*x^2+e*x+d)/(x^4-5*x^2+4)^2,x, algorithm="maxima")

[Out]

1/864*(19*d - 32*e + 52*f - 80*g + 112*h)*log(x + 2) - 1/108*(d - 4*e + 7*f - 10*g + 13*h)*log(x + 1) + 1/108*
(d + 4*e + 7*f + 10*g + 13*h)*log(x - 1) - 1/864*(19*d + 32*e + 52*f + 80*g + 112*h)*log(x - 2) - 1/72*((5*d +
8*f + 20*h)*x^3 + 4*(2*e + 5*g)*x^2 - (17*d + 20*f + 32*h)*x - 20*e - 32*g)/(x^4 - 5*x^2 + 4)

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mupad [B]  time = 0.87, size = 146, normalized size = 0.97 \begin {gather*} \frac {\left (-\frac {5\,d}{72}-\frac {f}{9}-\frac {5\,h}{18}\right )\,x^3+\left (-\frac {e}{9}-\frac {5\,g}{18}\right )\,x^2+\left (\frac {17\,d}{72}+\frac {5\,f}{18}+\frac {4\,h}{9}\right )\,x+\frac {5\,e}{18}+\frac {4\,g}{9}}{x^4-5\,x^2+4}+\ln \left (x-1\right )\,\left (\frac {d}{108}+\frac {e}{27}+\frac {7\,f}{108}+\frac {5\,g}{54}+\frac {13\,h}{108}\right )-\ln \left (x+1\right )\,\left (\frac {d}{108}-\frac {e}{27}+\frac {7\,f}{108}-\frac {5\,g}{54}+\frac {13\,h}{108}\right )-\ln \left (x-2\right )\,\left (\frac {19\,d}{864}+\frac {e}{27}+\frac {13\,f}{216}+\frac {5\,g}{54}+\frac {7\,h}{54}\right )+\ln \left (x+2\right )\,\left (\frac {19\,d}{864}-\frac {e}{27}+\frac {13\,f}{216}-\frac {5\,g}{54}+\frac {7\,h}{54}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d + e*x + f*x^2 + g*x^3 + h*x^4)/(x^4 - 5*x^2 + 4)^2,x)

[Out]

((5*e)/18 + (4*g)/9 - x^2*(e/9 + (5*g)/18) + x*((17*d)/72 + (5*f)/18 + (4*h)/9) - x^3*((5*d)/72 + f/9 + (5*h)/
18))/(x^4 - 5*x^2 + 4) + log(x - 1)*(d/108 + e/27 + (7*f)/108 + (5*g)/54 + (13*h)/108) - log(x + 1)*(d/108 - e
/27 + (7*f)/108 - (5*g)/54 + (13*h)/108) - log(x - 2)*((19*d)/864 + e/27 + (13*f)/216 + (5*g)/54 + (7*h)/54) +
log(x + 2)*((19*d)/864 - e/27 + (13*f)/216 - (5*g)/54 + (7*h)/54)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((h*x**4+g*x**3+f*x**2+e*x+d)/(x**4-5*x**2+4)**2,x)

[Out]

Timed out

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